$\int (2 x - 3 cos x + e^{x}) d x$ is equal to (where $C$ is the constant of integration)

x^{2} - 3 sin x + e^{x} + C

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x^{2} + 3 sin x + e^{x} + C

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x^{2} + 3 sin x + e^{- x} + C

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x^{3} + 3 sin x + e^{x} + C

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Solution

The correct option is A $x^{2} - 3 sin x + e^{x} + C$
By integrating the terms separately, we get
$= 2 \int x d x - 3 \int cos x d x + \int e^{x} d x = \frac{2 x^{2}}{2} - 3 (sin x) + e^{x} + C = x^{2} - 3 sin x + e^{x} + C$

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