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Question

(2x12+5x9)(1+x3+x5)3dx equals

A
x102(x5+x3+1)2+C
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B
x2+2x(x5+x3+1)+C
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C
log[x5+x3+1+2x12+5x9+C]
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D
None of the above
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Solution

The correct option is A x102(x5+x3+1)2+C
Let I=2x12+5x9(1+x3+x5)3dx
divide numerator and denominator by x15
=5x6+2x3(1+x2+x5)3dx
Put 1+x2+x5=t.(2x35x6)dx=dt
I=dtt2=12t2=12(1+x2+x5)2
=x102(x5+x3+1)2+C

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