$\int \frac{1}{2 + 3 x} d x$ .

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Solution

$\int \frac{1}{2 + 3 x} d x t = 2 + 3 x ⟹ 3 d x = d t ⟹ \int \frac{1}{3} \frac{1}{t} d t \frac{1}{3} log t + c \frac{1}{3} log (2 + 3 x) + c$

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