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Integration by Substitution

∫17x+6 dx

Question

$\int \frac{1}{7 x + 6} d x$

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Solution

$\int \frac{1}{7 x + 6} d x t = 7 x + 6 ⟹ 7 d x = d t \int \frac{1}{7} \frac{1}{t} d t \frac{1}{7} log t + c \frac{1}{7} log (7 x + 6) + c$

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