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Question

1sin3xsin(x+α)dx,anπ,nϵZ is equal to

A
2cscα(cosαtanxsinα)1/2+C
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B
2(cosα+cotxsinα)1/2+C
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C
2cscα(cosα+cotxsinα)1/2+C
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D
2cscα(sinα+cotxcosα)1/2+C
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Solution

The correct option is B 2(cosα+cotxsinα)1/2+C
dxsin3xsin(x+α)=dxsin2xcosα+cotxsinα=(cosα+cotxsinα)12d(cotx)
=2(cosα+cotxsinα)12+C

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