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B
2√x+2+2√3log∣∣∣√x+2−√3√x+2+√3∣∣∣+C
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C
2√x+2−2√3log∣∣∣√x−2−√3√x+2+√3∣∣∣+C
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D
2√x+2+2√2log∣∣∣√x−2−√3√x+2+√3∣∣∣
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Solution
The correct option is B2√x+2+2√3log∣∣∣√x+2−√3√x+2+√3∣∣∣+C I=∫x+1(x−1)√x+2dx Let x+2=t2 or dx=2tdt ∴I=∫t2−1(t2−3)t2tdt =2∫t2−3+2(t2−3)dt =2∫(1+2(t2−3))dt =2t+2√3log∣∣∣t−√3t+√3∣∣∣+C =2√x+2+2√3log∣∣∣√x+2−√3√x+2+√3∣∣∣+C