CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

x+2x2+2x+3dx

Open in App
Solution

x+2x2+2x+3dx let x2+2x+3=t
=x+1+1x2+2x+3dx (2x+2)dx=2tdt (x+1)dx=tdt
=x+1x2+2x+3dx +1x2+2x+3dx
=ttdt +1(x+1)2+2dx
=t+ln(x+1)+(2+(x+1)2)+C
=(x2+2x+3)+ln(x+1)+(2+(x+1)2)+C



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon