$\int \frac{x}{x + 1} d x$

Open in App

Solution

$\int \frac{x}{x + 1}$
$\Rightarrow \int \frac{x + 1 - 1}{x + 1}$
$\Rightarrow \int 1 - \frac{1}{x + 1}$
$= x - l n (x + 1) + c$ .

Suggest Corrections

Similar questions

$\int \frac{x}{\sqrt{x} + 1} d x$

\int \frac{x^{3} + x + 1}{x^{2} - 1} d x

\int \frac{x^{3} + x + 1}{x^{2} - 1} d x

\int (x + 1) \sqrt{x^{2} + x + 1} d x

\int (x + 2) \sqrt{x + 1} d x =

\int \frac{x}{x^{2} + x + 1} d x

Join BYJU'S Learning Program