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Question

dxx(logx2)(logx3)=

A
1xloglogx3logx2
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B
loglogx3logx2
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C
loglogx2logx3
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D
log|(logx3)(logx2)|
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Solution

The correct option is B loglogx3logx2
Let I=dxx(logx2)(logx3)
Substitute logx=t1xdx=dt
I=dt(t2)(t3) =[(t2)(t3)]dt(t2)(t3)
=log|t3|ln|t2|=logt3t2=loglogx3logx2

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