-83-8cosx-cosx-sinxdx-

The correct option is B π/8 I=∫_π8^3π8cos #160; #10;xsin #160; x+ #160; cos #160; xdx #10; ∫_0^af(x)dx=∫_0^af(a+b x)dx #10; ∫ ...

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Chain Rule of Differentiation

∫π/83π/8cosx/...

Question

$\int_{\frac{π}{8}}^{\frac{3 π}{8}} \frac{c o s x}{c o s x + s i n x} d x =$

\frac{π}{6}

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\frac{π}{8}

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\frac{π}{12}

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\frac{π}{24}

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Solution

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Similar questions

\int_{0}^{π / 2} \frac{cos x}{cos x + sin x} d x

A = π \int 0 \frac{sin x d x}{sin x + cos x}

B = π \int 0 \frac{sin x d x}{sin x - cos x}

A = π \int 0 \frac{sin x d x}{sin x + cos x}

B = π \int 0 \frac{sin x d x}{sin x - cos x}

g_{i} : [\frac{π}{8}, \frac{3 π}{8}] \to R, i = 1, 2

f : [\frac{π}{8}, \frac{3 π}{8}] \to R

g_{1} (x) = 1, g_{2} (x) = | 4 x - π |

f (x) = {sin}^{2} x,

x \in [\frac{π}{8}, \frac{3 π}{8}] .

S_{i} = \int_{\frac{π}{8}}^{\frac{3 π}{8}} f (x) \cdot g_{i} (x) d x, i = 1, 2

\frac{16 S_{1}}{π}

The maximum value of $s i n (x + \frac{π}{6}) + c o s (x + \frac{π}{6})$ in the

interval $(0, \frac{π}{2})$ is attained at

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