$\int (e^{2 x} + x^{3} + sin x) d x$ is equal to
(where $C$ is constant of integration)

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Solution

$\int (e^{2 x} + x^{3} + sin x) d x = \int e^{2 x} d x + \int x^{3} d x + \int sin x d x$
$= \frac{e^{2 x}}{2} + \frac{x^{4}}{4} - cos x + C$

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