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Question

ex[log(x+x21)+ddx(cosh1x)]dx=

A
exsinh1x+c
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B
exlog(x+x2+1)+c
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C
excosh1x+c
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D
exsinh1x+c
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Solution

The correct option is D excosh1x+c
ex[log(x+x21)+ddx(cosh1x)]dx

ex[cosh1x+ddx(cosh1x)]dx

we know that
log(x+x21)=cosh1x

so it is in the form of
en[f(x)+f1(x)]dx
=exf(x)+c

so,
en(log (x+x2+1)+ddx(cos h1x)]dx
=ex.cosh1x+c

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