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Question

exsecx(1+tanx) dx is equal to
(where c is integration constant)

A
extanx+c
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B
ex(secx+tanx)+c
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C
exsecx+c
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D
ex(secxtanx)+c
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Solution

The correct option is C exsecx+c
I=exsecx(1+tanx)dx =ex(secx+secxtanx)dx f(x) f(x)I=exsecx+c[ex(f(x)+f(x))dx=exf(x)+c]

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