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Question

ex(sinx+cosx)dx=

A
exsinx+c
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B
excosx+c
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C
ex(sinxcosx)+c
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D
excosx+c
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Solution

The correct option is B exsinx+c
we know that ex[f(x)+f(x)]dx= ex f(x)+c
so, ex(sinx+cosx)dx= exsinx+c

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