wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

1419dx(1x)x=log32

Open in App
Solution

I=1/41/9dx(1x)x
Let x=t limit , at 1/9=t=13
12xdx=dt at x=14,14=t=12
dxx=2dt
I=1/21/32dt(1t2)
=[22log1+t1t]1/21/3
22[log1+1/211/2log1+1/311/3]
=log32

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon