wiz-icon
MyQuestionIcon
MyQuestionIcon
13
You visited us 13 times! Enjoying our articles? Unlock Full Access!
Question

1cosxcosx(1+cosx)dx.

A
log(secxtanx)2tanx2.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
log(secx+tanx)tanx2.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
log(secx+tanx)+2tanx2.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
log(secx+tanx)2tanx2.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D log(secx+tanx)2tanx2.
1cosxcosx(1+cosx)=1cosx21+cosx P.F.'S
I=[secx2/2cos2(x/2)]dx
=log(secx+tanx)2tanx2.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Partial Fractions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon