No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
log[log(logx)].
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
log[log(logx2)].
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−log[log(logx)].
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Blog[log(logx)]. Let I=∫1xlogxlog(logx)dx Put log(logx)=t⇒1logx1xdx=dt Therefore I=∫1tdt=logt=log[log(logx)] Hence, option 'B' is correct.