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Question

1xlogxlog(logx)dx.

A
[log(logx)].
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B
log[log(logx)].
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C
log[log(logx2)].
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D
log[log(logx)].
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Solution

The correct option is B log[log(logx)].
Let I=1xlogxlog(logx)dx
Put log(logx)=t1logx1xdx=dt
Therefore
I=1tdt=logt=log[log(logx)]
Hence, option 'B' is correct.

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