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Question

1xlogx[log(logx)]dx=

A
log|log(logx)|+c
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B
log|logx|+c
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C
log|logx|+c
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D
log|log(logx)|+c
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Solution

The correct option is A log|log(logx)|+c
1x log x[log(log x)]dx
d log x= 1/x.dx
d log xlog x[log(log x)]
log x = t
dtt[log t]
=[dlog(t)]log(t)
logt=p
=logp+c
=log(logt)+c
=log|log(log x)|+c
1x log x[log(log x)]=log|log(log x)|+c

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