You visited us 1 times! Enjoying our articles? Unlock Full Access!

Arithmetic Progression

∫2x4+x3-4x2+4...

Question

$\int \frac{2 x^{4} + x^{3} - 4 x^{2} + 4 x + 2}{(x^{2} + 4) (x^{2} - 1)^{2}} d x$

{tan}^{- 1} \frac{x}{2} - \frac{1}{2} \cdot \frac{1}{x^{2} - 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{tan}^{- 1} \frac{x}{2} + \frac{1}{2} \cdot \frac{1}{x^{2} - 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{tan}^{- 1} \frac{x}{2} - \frac{1}{3} \cdot \frac{1}{x^{2} - 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{tan}^{- 1} \frac{x}{2} - \frac{1}{2} \cdot \frac{1}{x^{2} + 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A ${tan}^{- 1} \frac{x}{2} - \frac{1}{2} \cdot \frac{1}{x^{2} - 1}$
undefined

Suggest Corrections

Similar questions

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

3 {s i n}^{- 1} \frac{2 x}{1 + x^{2}} - 4 {c o s}^{- 1} \frac{1 - x^{2}}{1 + x^{2}} + 2 {t a n}^{- 1} \frac{2 x}{1 - x^{2}} = \frac{π}{3}

s i n [(1 / 5) {c o s}^{- 1} x] = 1

{t a n}^{- 1} \sqrt{x^{2} + x} + {s i n}^{- 1} \sqrt{x^{2} + x + 1} = \frac{π}{2}

\int \frac{(x^{2} + 1) d x}{(x^{2} + 2) (2 x^{2} + 1)} = \frac{1}{3 \sqrt{(2)}} {{tan}^{- 1} \frac{x}{\sqrt{(2)}} + {tan}^{- 1} x \sqrt{2}} .

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

0 < x < 1

\sqrt{1 + x^{2}} {[{x c o s ({c o t}^{- 1} x) + s i n ({c o t}^{- 1} x)}^{2} - 1]}^{1 / 2}

\frac{x}{\sqrt{1 + x^{2}}}

x

x \sqrt{1 + x^{2}}

\sqrt{1 + x^{2}}

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

{t a n}^{- 1} \frac{\sqrt{1 + x^{2}} - \sqrt{1 - x^{2}}}{\sqrt (1 + x^{2}) + \sqrt (1 + x^{2})} = α

x^{2} = s i n 2 α

\frac{m t a n (α - θ)}{{c o s}^{2} θ} = \frac{n t a n θ}{{c o s}^{2} (α - θ)}

θ = \frac{1}{2} [α - {t a n}^{- 1} (\frac{n - m}{n + m} t a n α)]

{c o s}^{- 1} \frac{c o s α + c o s β}{1 + c o s α c o s β} = 2 {t a n}^{- 1} (t a n \frac{α}{2} t a n \frac{β}{2})

c o s [t a n^{- 1} {s i n (c o t^{- 1} x)}] = \sqrt{\frac{1 + x^{2}}{2 + x^{2}}}

Join BYJU'S Learning Program