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Question

dxcos3x(sin2x)=25(t2+5)t. where t=tanx.
If this is true enter 1, else enter 0.

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Solution

Let I=dxcos3x(sin2x)
Put sin2x=2tanx1+tan2x
I=sec2x.sec2x(2tanx)dx=12(1+t2)tdt
=12(1t+t3/2)dt=25(t2+5)t

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