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Question

ln(x)x1+ln(x)dx equlas

A
231+ln|x|(ln|x|2)+c
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B
431+ln|x|(ln|x|2)c
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C
131+ln|x|(ln|x|2)+c
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D
21+ln|x|(3ln|x|2)+c
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Solution

The correct option is A 231+ln|x|(ln|x|2)+c
Let I=ln(x)x1+lnxdx
Substitute t=lnxdt=1xdx

I=tt+1dt

Substitute t=u+1dt=du

I=u1udu=(u1u)du
=2u2332u+c
=23(lnx2)322lnx+1
=23(ln|x|2)ln|x|+1

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