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Question

sin 2xsin4x+cos4xdx is equal to tan1(f(x)n)+C, then which of the following is/are correct ?

A
f(x)=tanx
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B
f(x)=cotx
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C
n=2
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D
n=4
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Solution

The correct option is C n=2
I=sin2xsin4x+cos4xdx
=2sinxcos xsin4 x+cos4xdx
=2tanxsec2 x1+tan4xdx
Let tan2x=t2tanxsec2xdx=dt
I=dt1+t2=tan1t+C=tan1(tan2x)+C

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