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Question

cotxtanx2(cosx+sinx)dx equals to

A
sec1(sinx+cosx)+c
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B
sec1(sinxcosx)+c
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C
ln|(sinx+cosx)+sin2x|+c
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D
ln|(sinxcosx)+sin2x|+c
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Solution

The correct option is C ln|(sinx+cosx)+sin2x|+c
Let I=cotxtanx2(cosx+sinx)dx
=(cosxsinx)2cosxsinx(cosx+sinx)dx
=(cosxsinx)sin2x(cosx+sinx)dx
Put cosx+sinx=t(sinx+cosx)dx=dt

And (cosx+sinx)2=t22sinxcosx=t21sin2x=t21

I=dtt21

=log(t21+t)+c

=ln|(sinx+cosx)+sin2x|+c

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