CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

cotxtanx2(cosx+sinx)dx equals to

A
sec1(sinx+cosx)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
sec1(sinxcosx)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
ln|(sinx+cosx)+sin2x|+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
ln|(sinxcosx)+sin2x|+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C ln|(sinx+cosx)+sin2x|+c
Let I=cotxtanx2(cosx+sinx)dx
=(cosxsinx)2cosxsinx(cosx+sinx)dx
=(cosxsinx)sin2x(cosx+sinx)dx
Put cosx+sinx=t(sinx+cosx)dx=dt

And (cosx+sinx)2=t22sinxcosx=t21sin2x=t21

I=dtt21

=log(t21+t)+c

=ln|(sinx+cosx)+sin2x|+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Irrational Algebraic Fractions - 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon