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Byju's Answer
Standard XII
Mathematics
Integration by Partial Fractions
∫√ x cos x /√...
Question
∫
√
x
cos
x
√
x
d
x
A
2
sin
exp
√
x
+
c
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B
2
cos
exp
√
x
+
c
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C
sin
exp
√
x
+
c
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D
sin
e
x
+
c
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Solution
The correct option is
A
2
sin
exp
√
x
+
c
Substitute
√
x
=
t
1
2
1
√
x
.
d
x
=
d
t
⇒
1
√
x
d
x
=
2
d
t
∫
2
e
t
c
o
s
e
t
d
t
.
Substitute
e
t
=
p
⇒
e
t
⋅
d
t
=
d
p
.
2
∫
cos
p
d
p
=
2
sin
p
+
c
sin
e
t
+
c
=
s
i
n
e
√
x
+
c
So,
∫
e
√
x
c
o
s
e
√
x
√
x
d
x
=
2
s
i
n
e
√
x
+
c
.
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