-x2-1-x3-2x4-2x2-1dx is equal to

The correct option is D 1/2x^2·√(2x^4 2x^2+1)+c ...

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Integration by Partial Fractions

∫x2-1/x3·√2x4...

Question

$\int \frac{x^{2} - 1}{x^{3} \cdot \sqrt{2 x^{4} - 2 x^{2} + 1}} d x$ is equal to

\frac{1}{x^{2}} \cdot \sqrt{2 x^{4} - 2 x^{2} + 1} + c

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\frac{1}{x^{3}} \cdot \sqrt{2 x^{4} - 2 x^{2} + 1} + c

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\frac{1}{x} \cdot \sqrt{2 x^{4} - 2 x^{2} + 1} + c

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\frac{1}{2 x^{2}} \cdot \sqrt{2 x^{4} - 2 x^{2} + 1} + c

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Solution

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Similar questions

\int \frac{x^{2} - 1}{x^{3} \sqrt{2 x^{4} - 2 x^{2} + 1}} d x

\int \frac{(x^{2} - 1) d x}{x^{3} (\sqrt{2 x^{4} - 2 x^{2} + 1})}

\int \frac{x^{2} - 1}{x^{3} \sqrt{2 x^{4} - 2 x^{2} + 1}} d x

\int \frac{x^{2} - 1}{x^{3} \sqrt{2 x^{4} - 2 x^{2} + 1}}

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