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Question

cos4x+1cotxtanxdx=

A
18cos4x+C
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B
14cos4x+C
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C
14cos4x+C
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D
18cos4x+C
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Solution

The correct option is D 18cos4x+C
cos4x+1cotxtanxdx
=cos4x+1cos2xsin2xsinxcosxdx
=2cos22xcos2xsinx.cosx dx
=cos2x.sin2x dx
=12sin4x dx
=18cos4x+C

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