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B
e100−1e−1
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C
100(e−1)
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D
e−1100
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Solution
The correct option is C100(e−1) We know that x−[x]={x} where {x} represents the fractional part of x. Fundamental period of {x} is 1 ∴100∫0ex−[x]dx=100∫10exdx=100[ex]10=100(e−1)