∫_0^π/2sin x. dx =∫_0^π/2 cos x dx =[ cos x]^π/2_0 = [ cos ( π2 ) cos 0 ] = [0 1] =1 ...

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Definite Integrals

∫0π/2sin x. d...

Question

$π / 2 \int 0 sin x . d x =$

0

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\frac{1}{2}

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1

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\frac{1}{4}

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Solution

The correct option is C $1$
$π / 2 \int 0 sin x . d x = π / 2 \int 0 - cos x d x$
$= [- cos x]_{0}^{π / 2} = - [cos (\frac{π}{2}) - cos 0] = - [0 - 1]$

$= 1$

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