Question

$\underset{0}{\overset{\pi /2}{\int }}\sin x.dx=$

• A. $0$
• B. $\frac{1}{2}$
• C. $1$
• D. $\frac{1}{4}$

Answer 1

The correct option is C $1$

$\underset{0}{\overset{\pi /2}{\int }}\sin x.dx=\underset{0}{\overset{\pi /2}{\int }}-\cos xdx$
$=[-\cos x{]}_0^{\pi /2}=-[\cos \left(\frac{\pi }{2}\right)-\cos 0]=-[0-1]$

$=1$