- -1 1 -x- dx - a then -

The correct option is A a=1 Given, ∫_ 1 ^ 1 |x| dx =2∫_ 0 ^ 1 x dx [ Since |x| is an even function] =2×[x^22]_0^1 =2×12 =1 ...

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Standard XII

Mathematics

Property 2

∫ -1 1 |x| dx...

Question

$1 \int - 1 | x | d x = a$ then -

a = 1

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a = 2

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a = 3

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a = 4

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Solution

The correct option is A $a = 1$
Given,
$1 \int - 1 | x | d x$
$= 2 1 \int 0 x d x$ [ Since $| x |$ is an even function]
$= 2 \times {[\frac{x^{2}}{2}]}_{0}^{1}$
$= 2 \times \frac{1}{2}$
$= 1$ .

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1∫−1|x|dx=a then -

The correct option is A a=1Given,1∫−1|x|dx=21∫0xdx [ Since |x| is an even function]=2×[x22]10=2×12=1.

$1 \int - 1 | x | d x = a$ then -

The correct option is A $a = 1$
Given,
$1 \int - 1 | x | d x$
$= 2 1 \int 0 x d x$ [ Since $| x |$ is an even function]
$= 2 \times {[\frac{x^{2}}{2}]}_{0}^{1}$
$= 2 \times \frac{1}{2}$
$= 1$ .