CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

31(x2+14x)1dx=______

A
log5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12log5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
log25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
log100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C log25
31(x2+14x)1dx
=314xx2+1dx
=312(2xx2+1)dx
=2[log(x2+1)]31
=2(log10log2)
=2log5=log25

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 2
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon