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Question

31(x2+14x)1dx=______

A
log5
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B
12log5
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C
log25
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D
log100
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Solution

The correct option is C log25
31(x2+14x)1dx
=314xx2+1dx
=312(2xx2+1)dx
=2[log(x2+1)]31
=2(log10log2)
=2log5=log25

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