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Question

π/20sinxcosxcos2x+3cosx+2dx=?

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Solution

π/20sinxcosxcos2x+232cosx+9494+2dx
π/20sinxcosx(cosx+32)214dx
Putting cosx+32=m
sinx=dm
10m32m214dm
10m121m214dm
101m+12dm101m214dm
log|m+12|101m12dm+101m+12dm
log|m+12|2|m12|
log9/41/2=log92



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