-4-4ex-2xdxe2x-1 is equal to-

The correct option is B 0 f( x ) = f( x ) #160; It is odd function put x= x I=∫ _ π #160; / 4 #160; ^π #160; / 4 ...

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Integration as Antiderivative

∫π/4-π/4ex·2x...

Question

$\int_{- π / 4}^{π / 4} \frac{e^{x} \cdot {sec}^{2} x d x}{e^{2 x} - 1}$ is equal to?

0

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Solution

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Similar questions

$\int_{- \frac{π}{4}}^{\frac{π}{4}} \frac{e^{x} . s e c^{2} x d x}{e^{2 x} - 1}$ is equal to

\int_{- π / 4}^{π / 4} \frac{e^{x} {sec}^{2} x d x}{e^{2 x} - 1}

I = \int_{\frac{- π}{4}}^{\frac{π}{4}} \frac{e^{sec x} | sin x | {sec}^{2} x d x}{(1 + e^{sin x})}

$\int_{- \frac{π}{4}}^{\frac{π}{4}} \frac{e^{x} . s e c^{2} x d x}{e^{2 x} - 1}$ is equal to

I = \int \frac{1}{e^{2 x} + e^{- 2 x}} d x = \frac{A}{842} {tan}^{- 1} e^{2 x} + C

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