The correct option is B 13(2x+5)^3/2 ∫√(2x+5) dx 2x+5=t 2dx=dt 1/2∫√(t) dt 13t^3/2 13(2x+5)^3/2+c ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration by Substitution

∫√2x+5dx

Question

$\int \sqrt{2 x + 5} d x$

\frac{1}{\sqrt{2 x + 5}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3} (2 x + 5)^{3 / 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{3}{5} (2 x + 5)^{3 / 5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2 x + 5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{1}{3} (2 x + 5)^{3 / 2}$
$\int \sqrt{2 x + 5} d x 2 x + 5 = t 2 d x = d t \frac{1}{2} \int \sqrt{t} d t \frac{1}{3} t^{3 / 2} \frac{1}{3} (2 x + 5)^{3 / 2} + c$

Suggest Corrections

Similar questions

\int \sqrt{x^{2} + 2 x + 5} dx is equal to

x

{(\frac{3}{5})}^{3} \times {(\frac{3}{5})}^{- 6} = {(\frac{3}{5})}^{1 - 2 x}

\int \sqrt{(x^{2} + 2 x + 5)} d x

5 (2 x + 1) (3 x + 5) \div (2 x + 1)

5 (2 x + 1) (3 x + 5) \div (2 x + 1)

Join BYJU'S Learning Program