wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

cos xcos3 x1cos3xdx, x(0,π2)is equal to

Open in App
Solution

cos xcos3x1cos3xdx=cos x1cos3xsin xdx
=t1t3dt=t1(t32)2dt where cos x=t,sinxdx=dt
=2332t1(t32)2dt
=23cos1(t32)+C
=23cos1(cos32x)+C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon