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Question

cosec2(4x+9)dx is equal to
(where C is the constant of integration)

A
cot(4x+9)9+C
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B
cot(4x+9)9+C
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C
cot(4x+9)4+C
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D
cot(4x+9)4+C
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Solution

The correct option is D cot(4x+9)4+C
cosec2(4x+9)dx=cot(4x+9)×14+C
(cosec2(ax+b) dx=cot(ax+b)a+C,a0)
=cot(4x+9)4+C

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