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Byju's Answer
Standard XII
Mathematics
Sign of Trigonometric Ratios in Different Quadrants
∫cosec 2x+5dx...
Question
∫
cosec
(
2
x
+
5
)
d
x
is equal to
(where
C
is constant of integration)
A
ln
|
cosec
(
2
x
+
5
)
+
cot
(
2
x
+
5
)
|
2
+
C
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B
ln
|
cosec
(
2
x
+
5
)
+
cot
(
2
x
+
5
)
|
5
+
C
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C
−
ln
|
cosec
(
2
x
+
5
)
+
cot
(
2
x
+
5
)
|
5
+
C
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D
−
ln
|
cosec
(
2
x
+
5
)
+
cot
(
2
x
+
5
)
|
2
+
C
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Solution
The correct option is
D
−
ln
|
cosec
(
2
x
+
5
)
+
cot
(
2
x
+
5
)
|
2
+
C
∫
cosec
(
2
x
+
5
)
d
x
=
−
ln
|
cosec
(
2
x
+
5
)
+
cot
(
2
x
+
5
)
|
2
+
C
(
∵
∫
cosec
(
a
x
+
b
)
d
x
=
−
ln
|
cosec
(
a
x
+
b
)
+
cot
(
a
x
+
b
)
|
a
+
C
,
a
≠
0
)
Suggest Corrections
0
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Sign of Trigonometric Ratios in Different Quadrants
Standard XII Mathematics
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