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Question

xe2x(1+x)dx equal to


A
xex2+c
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B
(ex)22r
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C
(1+x)22+c
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D
(xex)22
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Solution

The correct option is B (xex)22
I=xe2x(1+x)dx
=xe2xdx+x2e2xdx
=e2xx22x2e2xdx+x2e2xdx
I=(xex)22

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