KCl-conc H 2 SO 4 - K 2 Cr 2 O 7 - X NaOH Y KCl-conc H 2 SO 4 - K 2 Cr 2 O 7 - X NaOH Y- X is reddish brown coloured gas soluble in forming Y- X and Y are-

The correct option is D CrO _ 2 Cl _ 2 , Na _ 2 CrO _ 4 4KCl+ 3H _ 2 SO _ 4 + K _ 2 Cr _ 2 O _ 7 Δ #160; #160; yellow, chromyl chloride, ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Electron Gain Enthalpy

KCl+conc H 2 ...

Question

$K C l + c o n c H_{2} {S O}_{4} + K_{2} {C r}_{2} O_{7} Δ \to (X) N a O H - ---- \to (Y) K C l + c o n c H_{2} {S O}_{4} + K_{2} {C r}_{2} O_{7} Δ \to (X) N a O H - ---- \to (Y)$ . (X) is reddish brown coloured gas soluble in forming (Y). (X) and (Y) are___________.

{C r}_{2} {O C l}_{2}, {N a}_{2} {C r O}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C r}_{2} O_{2} {C l}_{2}, {N a}_{2} {C r O}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C r O}_{2} C l, {N a}_{2} {C r O}_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C r O}_{2} {C l}_{2}, {N a}_{2} {C r O}_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

$X + H^{+} ⟶ Y + N a^{+} + H_{2} O$

$Y + K C l ⟶ K_{2} C r_{2} O_{7} + N a C l$

Find X and Y.

K_{2} C r_{2} O_{7}

H_{2} S O_{4}

F e C r_{2} O_{4} + N a O H + a i r \to (A) + F e_{2} O_{3}

(A) + (B) \to N a_{2} C r_{2} 07

N a_{2} C r_{2} O_{7} + X Δ - \to C r_{2} O_{3}

C r_{2} O_{3} + Y Δ - \to C r

K_{2} C r_{2} O_{7}

H_{2} S O_{4}

C l O^{-} + C r O_{2}^{-} \to C l^{-} + C r O_{4}^{2 -}

Join BYJU'S Learning Program