${K O}_{2}$ exhibits paramagnetic behaviour. This is due to the paramagnetic nature of :

{K O}^{-}

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K^{+}

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O_{2}

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O_{2}^{-}

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Solution

The correct option is C $O_{2}^{-}$
$K O_{2}$ exhibits paramagnetic behaviour. This is due to the para-magnetic nature of ${O_{2}}^{-}$ ion which contains 1 unpaired electron in $π^{*} 2 p_{z}$ in MO.

Hence, option $D$ is correct.

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