Question

$(1+\frac{1}{2})(1+\frac{1}{3})(1+\frac{1}{4})(1+\frac{1}{5})(1+\frac{1}{6})(1+\frac{1}{7})(1+\frac{1}{8})$ is equal to

• A. 9
• B. 8
• C. 4.5
• D. None of these

Answer 1

Answer: (C)

4.5

$(1+\frac{1}{2})(1+\frac{1}{3})(1+\frac{1}{4})(1+\frac{1}{5})(1+\frac{1}{6})(1+\frac{1}{7})(1+\frac{1}{8})$
$\Rightarrow \frac{3}{2}\times \frac{4}{3}\times \frac{5}{4}\times \frac{6}{5}\times \frac{7}{6}\times \frac{8}{7}\times \frac{9}{8}$
$\Rightarrow \frac{9}{2}=4.5$