$(1 - {sin}^{2} θ) {sec}^{2} θ =$

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{tan}^{2} θ

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{cos}^{2} θ

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Solution

The correct option is B 1
We know that ${sin}^{2} θ + {cos}^{2} θ = 1$
$∴ 1 - {sin}^{2} θ = {cos}^{2} θ$
$⟹ 1 - {sin}^{2} θ = \frac{1}{{sec}^{2}}$
$⟹ (1 - {sin}^{2} θ) {sec}^{2} θ = 1$

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Similar questions

\frac{1 - cos 2 θ}{1 + cos 2 θ} = {tan}^{2} θ

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θ = 30^{\circ}

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