( 3a a^3/6 )^9 Here, n is odd therefore, middle terms are ( 9+1/2 ) th amp; ( 9+1/2+1 ) th #160;It means T_5 amp; T_6 ...

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General Term of Binomial Expansion

3a-a3/6 9

Question

${(3 a - \frac{a^{3}}{6})}^{9}$

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Solution

${(3 a - \frac{a^{3}}{6})}^{9}$
Here, $n$ is odd therefore, middle terms are $(\frac{9 + 1}{2})$ th & $(\frac{9 + 1}{2} + 1)$ th
It means $T_{5}$ & $T_{6}$ are middle terms
$T_{5} =^{9} C_{4} {(3 a)}^{9 - 4} {(- \frac{a^{3}}{6})}^{4} = \frac{189}{8} a^{17}$
$T_{6} =^{9} C_{5} {(3 a)}^{9 - 5} {(- \frac{a^{3}}{6})}^{5} = \frac{21}{16} a^{19} .$

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Similar questions

{(3 a - \frac{a^{3}}{6})}^{9}

{(3 a - \frac{a^{3}}{6})}^{9}

Simplify:

$a^{5} \div a^{3} + 3 a \times 2 a$

{(3 a - \frac{1}{a})}^{3}

2 x = a + \sqrt{\frac{4 b^{3} - a^{3}}{3 a}}

2 y = a - \sqrt{\frac{4 b^{3} - a^{3}}{3 a}}

x^{3} + y^{3}

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