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Question

(3x2−x2)5=x25[(6x)5−5(6x)4+A(6x)3−10(6x)2+5(6x)−1]. Find A

A
10
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B
20
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C
5
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D
15
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Solution

The correct option is A 10
(3x2x2)5
=x25(6x1)5
=x25[(6x)55C1(6x)4+5C2(6x)35C3(6x)2+5C4(6x)1]
=x25[(6x)55(6x)4+10(6x)310(6x)2+5(6x)1].
so, A=10

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