$(4^{61} + 4^{62} + 4^{63} + 4^{64})$ is divisible

3

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11

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13

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17

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Solution

The correct option is D $17$
$4^{61} + 4^{62} + 4^{63} + 4^{64} = 4^{61} (1 + 4 + 4^{2} + 4^{3})$
$= 4^{61} \times (1 + 4 + 16 + 64) = 4^{61} \times 85$
which is divisible by 17

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Similar questions

(4^{61} + 4^{62} + 4^{63} + 4^{64})

Without adding find the sum

(i) 1 + 3 + 5 + 7 + 9

(ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19

(iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

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