64 -2-3- 1-4 -3 equals

The correct option is B 4 (64)^ 23× ( 14 )^ 3=(4^3)^ 23× (4^ 1)^ 3 =4^ 2× 4^3 =4^ 2+3 =4^1 ...

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Summation by Sigma Method

64 -2/3× 1/4 ...

Question

${(64)}^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}$ equals

\frac{1}{4}

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Solution

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Similar questions

{lim}_{n \to \infty} \frac{1 + 1 + 4 + 8 + 9 + 27 + 16 + 64 + . . .}{(1 + 2 + 3 + 4 + 5 + . . .)^{2}} =

${{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}} \div {(\frac{1}{4})}^{- 3} = ?$

$(a) \frac{19}{64}$

$(b) \frac{27}{16}$

$(c) \frac{64}{19}$

$(d) \frac{16}{25}$

{(\frac{64}{125})}^{- 2 / 3} + \frac{1}{{(\frac{256}{625})}^{1 / 4}} + {(\frac{\sqrt{25}}{\sqrt[3]{64}})}^{0} = \frac{61}{16}

In ch .1

A question

to simplify

64^1/3(64^1/3 - 64^2/3)

in this the solution is given as

= (4^3)^ -1/3[ ( 4^3)^1/3 - (4^3)^2/3 ]

how -1/3 came ?

\lim_{x \to 4} \frac{x^{3} - 64}{x^{2} - 16}

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