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Question

∣∣ ∣∣0p−qp−rq−p0q−rr−pr−q0∣∣ ∣∣ is equal to

A
p+q+r
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B
0
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C
pqr
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D
p+q+r
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Solution

The correct option is A 0
∣ ∣0pqprqp0qrrprq0∣ ∣

=0(0(rq)(qr))(pq)(0(rp)(qr))+(pr)((qp)(rq)0)

=(pq)(rp)(qr)+(pr)(qp)(rq)=0

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