The correct option is A 3j+2k,√(13) ( i 2j+3k ) ×( 2j 3k ) =i( 6 6 ) j( 3 0 ) +k( 2 0 ) =3j+2k Length =√(( 3 ) nbsp;^ 2 +( 2 ) nbsp;^ 2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Vector Component

i-2j+3k × 2j-...

Question

$(i - 2 j + 3 k) \times (2 j - 3 k)$

3 j + 2 k, \sqrt{13}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 i + 2 k, \sqrt{13}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 j - 2 k, \sqrt{13}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 i - 2 k, \sqrt{13}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $3 j + 2 k, \sqrt{13}$
$(i - 2 j + 3 k) \times (2 j - 3 k) = i (6 - 6) - j (- 3 - 0) + k (2 - 0) = 3 j + 2 k$
Length $= \sqrt{{(3)}^{2} + {(2)}^{2}} = \sqrt{9 + 4} = \sqrt{13}$

Suggest Corrections

Similar questions

2 ¯ i - 3 ¯ j + 4 ¯ ¯ ¯ k, ¯ i - 2 ¯ j + 3 ¯ ¯ ¯ k

3 ¯ i + ¯ j - 2 ¯ ¯ ¯ k

¯ ¯ ¯ a = 2 ¯ i + 3 ¯ j + 6 ¯ ¯ ¯ k, ¯ ¯ ¯ b = 3 ¯ i - 6 ¯ j + 2 ¯ ¯ ¯ k, ¯ ¯ ¯ c = 6 ¯ i + 2 ¯ j - 3 ¯ ¯ ¯ k

¯ ¯ ¯ a \times ¯ ¯ ¯ b =

3 i + 5 j + 2 k, 2 i - 3 j - 5 k a n d - 5 i - 2 j + 3 k

[(3 i - 2 j - 2 k) \times (i - k)] \times [(i + j + k) \times (i - 2 j + 3 k)]

Join BYJU'S Learning Program