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Byju's Answer
Standard VIII
Mathematics
Algebraic Identities
[ 1+1/10+110...
Question
⎡
⎣
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
×
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
−
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
×
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
⎤
⎦
÷
⎡
⎣
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
+
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
⎤
⎦
simplifies to
A
100
101
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B
90
101
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C
20
101
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D
101
100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
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Solution
The correct option is
B
20
101
⇒
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
2
−
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
2
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
+
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
.....
(
a
2
−
b
2
)
=
(
a
+
b
)
(
a
−
b
)
⇒
⎡
⎣
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
+
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
⎤
⎦
⎡
⎣
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
−
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
⎤
⎦
⎡
⎣
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
+
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
⎤
⎦
⇒
⎛
⎝
1
+
1
10
+
1
10
⎞
⎠
−
⎛
⎝
1
−
1
10
+
1
10
⎞
⎠
⇒
⎛
⎜ ⎜ ⎜
⎝
1
+
1
101
10
⎞
⎟ ⎟ ⎟
⎠
−
⎛
⎜ ⎜ ⎜
⎝
1
−
1
101
10
⎞
⎟ ⎟ ⎟
⎠
⇒
(
1
+
10
101
)
−
(
1
−
10
101
)
⇒
(
101
+
10
101
)
−
(
101
−
10
101
)
=
(
111
101
)
−
(
91
101
)
=
20
101
Suggest Corrections
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