$[X] + H_{2} {S O}_{4} ⟶ [Y]$ a colourless gas with irritating smell
$[Y] + K_{2} {C r}_{2} O_{7} + H_{2} {S O}_{4} ⟶$ green solution
[X] and [Y] are:

{S O}_{3}^{2 -}, {S O}_{2}

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{C l}^{-}, H C l

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S^{2 -}, H_{2} S

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{C O}_{3}^{2 -}, {C O}_{2}

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Solution

The correct option is B ${S O}_{3}^{2 -}, {S O}_{2}$
${S O}_{3}^{2 -} [X] + H_{2} {S O}_{4} ⟶ {S O}_{2} [Y] + H_{2} O + S O_{4}^{2 -}$ . ${S O}_{2}$ is a colourless gas with irritating smell.

$3 {S O}_{2} [Y] + K_{2} {C r}_{2} O_{7} + H_{2} {S O}_{4} ⟶ K_{2} S O_{4} + C r_{2} (S O_{4})_{3} + H_{2} O$

[X] is ${S O}_{3}^{2 -}$ and [Y] is ${S O}_{2}$

The green colour of the solution is due to presence of chromium sulphate.

Option A is correct.

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Similar questions

[x] + H_{2} S O_{4} \to

[y] a colourless gas with irritating smell

[y] + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to

Green solution [x] and [y] are

[X] + H_{2} S O_{4} \to [Y]

a colourless gas with irritating smell

[Y] + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to

Green solution. [X] and [Y] are

[X] + H_{2} S O_{4} \to Y

, a colorless gas with irritating smell

[Y] + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to

Green solution, [X] and [Y] is

$X + H_{2} S O_{4} \to Y$
$Y + K_{2} C r_{2} O_{7} +$ $H_{2} S O_{4} \to$ Green solution.
$Y$ is a colorless gas with irritating smell.
$X$ and $Y$ are respectively:

Q. Balance the following equation by oxidation number method
i)

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

ii)

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

iii)

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

iv)

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

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[X]+H2SO4⟶[Y] a colourless gas with irritating smell[Y]+K2Cr2O7+H2SO4⟶ green solution[X] and [Y] are:

The correct option is B SO2−3,SO2SO2−3[X]+H2SO4⟶SO2[Y]+H2O+SO2−4 . SO2 is a colourless gas with irritating smell.3SO2[Y]+K2Cr2O7+H2SO4⟶K2SO4+Cr2(SO4)3+H2O [X] is SO2−3 and [Y] is SO2 The green colour of the solution is due to presence of chromium sulphate.Option A is correct.

$[X] + H_{2} {S O}_{4} ⟶ [Y]$ a colourless gas with irritating smell
$[Y] + K_{2} {C r}_{2} O_{7} + H_{2} {S O}_{4} ⟶$ green solution
[X] and [Y] are: